http://d.puremagic.com/issues/show_bug.cgi?id=8750



--- Comment #1 from Daniel Cousens <daniel...@bigpond.com> 2012-10-03 21:38:47 
PDT ---
The intention of the above is: all!(x => x in R)(sw).
Therefore, the clearer code (still fails) would be: all!(x => any!(x)(R))(sw)

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