--- Comment #14 from 2012-10-07 05:51:58 PDT ---
(In reply to comment #12)

> It is still a corner case of language spec, but I think it is an expected
> behavior.
> Because, the operator overloading mechanism just consider whether the function
> named opXXXX exists or not, and doesn't consider whether the opXXXX is really
> static or not.

See a discussion thread:

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