Jonathan M Davis <> changed:

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--- Comment #1 from Jonathan M Davis <> ---
I'm not sure what is and isn't supposed to be legal with the comma operator
now, but if the issue is that the statement has no effect, then there isn't
necessarily a bug here, because f isn't pure. Yes, _we_ can see that f has no
effect, but the compiler doesn't look past the signature. Now, I slapped pure
on f to see what would happen, and that still doesn't produce an error, so
there probably is a bug if your example has pure on f, but as-is, I'm not sure
that it actually shows a bug.


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