Re: How to get a function name (string) @ compile time

[Denis Koroskin]

On Mon, 03 Nov 2008 01:59:56 +0300, Daniel Ribeiro Maciel  
<[EMAIL PROTECTED]> wrote:

How do we get a function name (string) @ compile time?
I need to do stuff like (in C)

#include <stdio.h>

#define HELLO( func ) \
  printf( "calling " #func "\n" ); \
  func();

void foo()
{
        printf( "@foo" );
}

int main()
{
        HELLO( foo );
        printf( "\n" );
}

The output is:
calling foo
@foo

Thanks in advance,
Daniel


Just in case you know little D here is the source code, explanation and  
comparison to C++:

import std.stdio; // this is used to import writefln() - a function  
similar to printf (but typesafe)

// this is a template function that takes almost anything (close to C++  
templates and C macros)
void print(alias functionName)()
{
    // stringof is used to take a string representation of the identifier
    writefln("Calling ", functionName.stringof);

    // let's invoke it! This will succeed if functionName is a function,  
pointer to function,
    // delegate or an object that have overloaded opCall() (similar to C++  
operator())
    functionName();
}

void foo()
{
    writefln("@foo"); // same as printf("@foo);
}

void main()
{
    // foo is a global (free) function. it is passed to the template  
function.
    // In C++ you would do print<foo>(); (but C++ doesn't support  
specializing
    // templates with functions nor does it have .stringof)
    print!(foo);
}