Christopher Wright wrote:
It's an implicit narrowing conversion -- that involves data loss. This is a bug.
Actually, you said you had two methods, something like this:
void foo (byte i) {}
void foo (long i) {}
void main ()
{
int a = 1;
foo (a);
byte b = a; // no casts
}
This example doesn't use typedefs but still complains about overloads. I
find it odd that you can implicitly cast an arithmetic type of one width
to another of a smaller width. I'm making a feature enhancement request
for this.
