Re: Factory class

[Denis Koroskin]

On Thu, 19 Mar 2009 22:58:02 +0300, Simen Kjaeraas <simen.kja...@gmail.com> 
wrote:

On Thu, 19 Mar 2009 18:06:37 +0100, KeepYourMind <vyaches...@blue-code.org> wrote:

Sean Kelly Wrote:

KeepYourMind wrote:
>
> What i need to do for pizza.doSomeA() begin work?

cast pizza to CoolPizza.

Problem is i dont know what class returned. "char[] name" is dynamic and getting from command-line arguments.

Then you need some test to see if it really is a CoolPizza.

void main( string[] args ) {
    auto pizza = PizzaFactory.factory( args[1] );
    pizza.doSome( );
    if ( args[1] == "CoolPizza" ) {
        ( cast( CoolPizza ) pizza ).doSomeA( );
    }
}

Not like that. Here is a better way:

auto pizza = PizzaFactory.factory( name );
pizza.doSome();
if (auto cool = cast(CoolPizza)pizza) {
   cool.doSomeA();
}