On Tue, 20 Oct 2009 08:58:17 -0400, Qian Xu <[email protected]>
wrote:
Chris Nicholson-Sauls wrote:
Qian Xu wrote:
Hi All,
a function is declared as follows:
class Foo
{
final Value array(...)
{
...
}
}
I can pass any number of parameters to this method array() like:
auto foo = new Foo;
foo.array(1, 2, 3);
But if I have only an array in hand, how to pass it to this method? Is
it
possible?
int[] myarray = [1, 2, 3];
// how to pass "myarray" to foo.array(...)
Best regards
If you only intend Foo.array() to accept params of a particular type,
just
an arbitrary number of them, there's a syntax that marries variadic
arguments and arrays together:
class Foo {
final Value array (int[] args ...) {
...
}
}
This will allow any number of int's to be passed, which are quietly
packaged as an int[],
and also transparently accepts int[] as-is. Obviously, though, it isn't
any help if you need to accept various types, and I'm not sure how well
std.variant plays with this.
-- Chris Nicholson-Sauls
I have forgotten to say, that the class Foo comes from an external
d-library
(tango), which means that I am not able to change the function interface.
I can only use the method foo.array(...)
typically, tango calls a non-variadic version of a variadic function with
the array and type array. You can see if there is a non-variadic version
to call instead.
However, it would be a nice feature to be able to signify you want to
package the args yourself, rather than having to resort to this kind of
stuff. I'm sure a library solution is possible.
-Steve
