On Fri, 18 Dec 2009 13:49:18 -0500, div0 <d...@users.sourceforge.net>
wrote:
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Steven Schveighoffer wrote:
If I have 2 identical floating point values, how do I ensure they are
binary equivalents of eachother? I'm trying to write some
unittest/assert code, and it's not exactly trivial.
I thought 'a is b' would work, but it just morphs into a == b, which
isn't helpful. Why doesn't 'is' just do a bit compare for floating
points?
-Steve
Just out of curiosity; how many cases are there where a == b
and they have different bit patterns?
I can only think of +-0.
Otherwise you can only get that with denormalised floats;
which you won't get on an x86 processor.
nan is the specific one I was trying to test for.
From my very hazy memory, I think there can even be multiple binary
representations of nan, but I'm not sure.
-Steve
