Steven Schveighoffer wrote:
On Mon, 08 Mar 2010 09:38:08 -0500, Ary Borenszweig
<a...@esperanto.org.ar> wrote:
The following compiles:
import std.stdio;
interface I {
}
class A : I {
}
class B {
}
int main() {
I i = new A();
A a = cast(A) i;
B b = cast(B) i; // shouldn't compile
B c = cast(B) a; // shouldn't compile
writeln(a);
writeln(b);
writeln(c);
return 0;
}
But two lines there doesn't make sense:
B b = cast(B) i;
An instance of I can never be a B, so why the cast is allowed?
class C: B, I {}
I i = new C;
B b = cast(B)i; // should work
Ah, good one! I just tested it in Java and it also compiles, so I was wrong.
B c = cast(B) a;
An instance of A can never be an A, so why the cast is allowed?
Aside from the typo, I agree with you there, this should never be
possible, because a derived class can not inherit both B and A.
Where's the typo?
I think these casts should result in an error. This can prevent some
bugs.
Java and C# work like that. You can't cast an object of instance of
type A to type B if both types are classes and B isn't a supertype or
subtype of A.
This rule makes sense. On the other hand, I wonder how the new ability
to cast to any type works in terms of classes. Can you define
cast!(A)() in B for instance? I suppose you could make a caveat that
either the class must inherit A or define an opCast for A.
Yes, you'd always have to also check if an opCast is present.
-Steve