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strtr wrote:
> == Quote from div0 (d...@users.sourceforge.net)'s article
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>> strtr wrote:
>>> Or more to the point:
>>>
>>> Can (Class) template mixin functions be devirtualized by the compiler or do
>>> I (as
>>> optimization) need to manually copy paste the boiler plate code?
>> You can just wrap the mixin in a final block:
>> import std.stdio;
>> template bar(T) {
>> void test(T t) {
>> writefln("t: %s", t);
>> }
>> }
>> class foo {
>> final {
>> mixin bar!(int);
>> }
>> }
>> int main(){
>> scope f = new foo;
>> f.test(3);
>> return 0;
>> }
>
> Is that different from making all functions within the template final?
>
Well it delegates the choice of virtual versus non virtual to the class
using the mixin. No idea if that's a good idea or a bad one; I guess
you'd have to think very carefully about what your mixin is trying to
achieve.
I just tried marking a function in the template final
and that seems to work as well, so you could have a mix of virtual and
non virtual in a template, but that feels like a hackish design.
So you can it appears do this: (though that's dmd 2.028)
template bar(T) {
final:
void test(T t) {
writefln("t: %s", t);
}
void test2() {
}
}
class foo {
mixin bar!(int);
}
int main(){
foo f = new foo;
f.test(3);
f.test2();
return 0;
}
- --
My enormous talent is exceeded only by my outrageous laziness.
http://www.ssTk.co.uk
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