On 09/10/2010 04:40 AM, Andrej Mitrovic wrote:
I'm trying to use algorithm.copy, but I get back nothing in the copy buffer. How do I to copy an array of ubyte's?iimport std.algorithm, std.concurrency, std.stdio; void main() { enum bufferSize = 4; auto tid = spawn(&fileWriter); // Read loop foreach (ubyte[] buffer; stdin.byChunk(bufferSize)) { immutable(ubyte)[] copy_buffer; copy(buffer, copy_buffer); writeln(copy_buffer); // writes nothing send(tid, copy_buffer); } } void fileWriter() { while (true) { auto buffer = receiveOnly!(immutable(ubyte)[])(); // writeln(buffer); } } Andrej Mitrovic Wrote:This is from TDPL page 407: import std.algorithm, std.concurrency, std.stdio; void main() { enum bufferSize = 1024 * 100; auto tid = spawn(&fileWriter); // Read loop foreach (immutable(ubyte)[] buffer; stdin.byChunk(bufferSize)) { send(tid, buffer); } } void fileWriter() { // write loop while (true) { auto buffer = receiveOnly!(immutable(ubyte)[])(); tgt.write(buffer); } } Error: C:\DMD\dmd2\windows\bin\..\..\src\phobos\std\stdio.d(1943): Error: cannot implicitly convert expression (buffer) of type ubyte[] to immutable(ubyte)[] Yet interestingly I can't use type inference: foreach (buffer; stdin.byChunk(bufferSize)) { send(tid, buffer); } Error: stdin_stdout_copy.d(11): Error: cannot infer type for buffer But in the original code I get back a mutable ubyte[] which I can't implicitly convert to immutable (I'd need a copy first). There's no .dup or .idup property for stdin.byChunk. So what am I supossed to do here?
std.algorithm.copy will copy an input range into an output range. An array is a valid output range, but does not append as you seem to expect. Instead, it fills the array.
int[] a = new int[](3); copy([1,2,3],a); assert (a == [1,2,3]); To get an output range which appends to an array, use appender. In this case, however, you simply want buffer.idup; :-)
