spir wrote:
On Fri, 03 Dec 2010 17:49:47 -0500
"Steven Schveighoffer" <schvei...@yahoo.com> wrote:
just that i + i generates different instructions than ui + ui where int
i; uint ui;
Not really important, because I'm currently interested in cast only.
Thank you.
That is odd, I would think that i+i generates the same instructions as
ui+ui. As far as I know, adding unsigned and signed is the same
instruction, but unsigned add just ignores the carry bit.
That used to be true (at least on some machines, a long time ago).
Denis
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vit esse estrany ☣
spir.wikidot.com
It's only multiply, divide, and right shift where the instructions are
different.
