On 4/4/20 8:07 AM, Robert M. Münch wrote:
On 2020-04-04 10:32:32 +0000, Ferhat Kurtulmuş said:
Probably I didn't understand what you mean. Sorry if this is not the
case, but this one is easy.
...
struct S {
float a;
float b;
S opOpAssign(string op)(ref S rhs) if (op == "+"){
this.a += rhs.a;
this.b += rhs.b;
return this;
}
}
void main()
{
S a = {1, 5};
S b = {2, 5};
a += b;
writeln(a);
}
...
Yes, sure, but in C++ I don't have to explicitly write this down. It
just works. IMO that makes a lot of sense as long as all types fit. This
just looks superfluously.
steves@homebuild:~$ cat test.cpp
struct S
{
float a;
float b;
};
int main()
{
S a = {1, 5};
S b = {2, 5};
a += b;
}
steves@homebuild:~$ g++ -o test test.cpp
test.cpp: In function ‘int main()’:
test.cpp:11:4: error: no match for ‘operator+=’ (operand types are ‘S’
and ‘S’)
a += b;
~~^~~~
Doesn't seem to "just work" for me...
-Steve
