Re: How can I test at compile time whether T is an instance of an interface ?

[Otávio Augusto via Digitalmars-d-learn]

On Wednesday, 23 September 2020 at 18:37:45 UTC, wjoe wrote:

I have some similar functions:

void register(C: IFoo)()
{
  _insert!C();
}

void register(C)() if (behavesLikeFoo!C)
{
  _insert!C();
}

There are more overloads with parameters so I want to merge them

void register(C, ARGS...)(ARGS args) if (behavesLikeFoo!C || isInstanceOf!(C, IFoo))

{
  _insert!C(args);
}

I found a lot of information on how to do this at runtime but not at compile time. std.traits: isInstanceOf doesn't work. Neither did anything I tried with typeid etc.

The behavesLikeFoo constraint works as expected but it accepts any class no matter whether or not it implements the interface.

see if "import std.traits: isImplicitlyConvertible" helps you.