On 12/7/20 4:48 AM, Dukc wrote:
On Monday, 7 December 2020 at 08:16:50 UTC, mw wrote:
r = Parallel(n_jobs=2, verbose=10)(delayed(sleep)(.2) for _ in range(10))
to print out the progress.
How to do this in D's parallel loop?
thanks.
Allocate a `shared int` before the foreach loop. In the loop when, let's
say `!(i & 0xFFF)`, atomically increment the shared variable and print
it's number.
Disclaimer: no experience about using `shared`, but this is what I'd try.
Yes, that would be the way but I don't know the effect of using shared
or not. But because the progress needs to be somehow reported, an atomic
variable may not be sufficient (unless a separate thread is reading it,
etc.)
This issue came up during one of my recent presentations at this point:
https://www.youtube.com/watch?v=dRORNQIB2wA&feature=youtu.be&t=1527
I used a synchronized block in that code because it did not affect
performance in my use case.
Ali
