Convert double to long if lossless

[Per Nordlöw via Digitalmars-d-learn]

I want to convert a double to a long if conversion is lossless 
(without fractional part, non-nan, non-inf, within long-range, 
etc).

I currently have
void foo()
{
    const double value = 10.1;
    try
    {
        import std.conv : to;
        const lvalue = value.to!long;
        if (lvalue == value)
        {
            writeln("lvalue:", lvalue);
            return;
        }
    }
    catch (Exception e) {}
    writeln("value:", value);
}

Can this be improved?

For instance how do I check if a float/double/real has a 
fractional part and avoid entering try-catch for those cases?