On Tuesday, 19 January 2021 at 22:45:19 UTC, Paul Backus wrote:
On Tuesday, 19 January 2021 at 22:38:41 UTC, Tim wrote:
On Tuesday, 19 January 2021 at 22:36:47 UTC, Paul Backus wrote:
On Tuesday, 19 January 2021 at 22:34:04 UTC, Tim wrote:
On Tuesday, 19 January 2021 at 22:31:47 UTC, Paul Backus
wrote:
You've almost got it. The correct syntax is `is(T == U[],
U)`. You can read it as "there exists some type U such that
T == U[]".
Thanks! Do I need to specify U in the template function?
No, only inside the is(...) expression.
What if it is a static array i.e. double[3]?
is(T == U[n], U, size_t n)
Easy, thanks a lot!
