On 02/25/2011 07:52 PM, Andrej Mitrovic wrote:
So I'd like to print all values storable in a byte in hex representation:import std.stdio; void main() { int counter; foreach (byte index; byte.min..byte.max) { if (!(counter % 4)) writeln(); writef("%#.2x, ", index); counter++; } } If you run this, you'll realize that it doesn't print the final 0x7F. This is because in a foreach range literal (is that the correct term?), the left side is inclusive, but the right side isn't. Hence this will run the foreach from 0 to 9: foreach (index; 0..10) { } So I figured I'd just add a +1 at the end, but then I get an error: foreach (byte index; byte.min..byte.max+1) { } Error: cannot implicitly convert expression (128) of type int to byte. Of course 128 can't fit in a byte. But how am I supposed to print out the last value if the right hand side of a range literal is non-inclusive? This behavior is kind of odd, don't you think? byte.max is 127, but due to the way foreach works, the last value assigned to index is 126. If I was allowed to add +1 for RHS, the last value stored to index would be 127 due to the non-inclusive right side, which is completely legal. Yet DMD complains that I'm trying to store 128 to index. I guess DMD first checks if the value on the RHS of the range literal can fit to a byte before it cuts one off due to the way range literals work. So how do I work around this?
lol! One more source of fun in using half-open intervals :-) Denis -- _________________ vita es estrany spir.wikidot.com
