On Tuesday, 16 March 2021 at 16:29:45 UTC, Imperatorn wrote:
On Tuesday, 16 March 2021 at 13:52:29 UTC, Per Nordlöw wrote:
On Tuesday, 16 March 2021 at 13:31:34 UTC, Imperatorn wrote:
foreach(0..n) could work. Why though.
When performing a side-effect n times.
Then why not just do:
auto times(alias F, T)(T number)
{
return number.iota.each!(_ => F());
}
void f()
{
writeln("hi");
}
n.times!(f);
?
To my knowledge, there's nothing like this in the standard
library or the language. I used something similar but eventually
decided it was simpler to use the original foreach. It'd honestly
have to be a language change to be useful. (Given the benefit, I
doubt this would happen.)
