Re: cannot take address of scope local in safe function

[ag0aep6g via Digitalmars-d-learn]

On Sunday, 13 June 2021 at 16:27:18 UTC, vit wrote:
Why I can take address of Foo variable but not Bar?
```d
//-dip1000

struct Foo{
    private double d;
}

struct Bar{
    private void* ptr;
}



void main()@safe{
    ///this is OK:
    {
        scope Foo x;
        scope ptr = &x;
    }

    ///Error: cannot take address of `scope` local `x` in 
`@safe` function `main`:
    {
        scope Bar x;
        scope ptr = &x;
    }
}
```

`scope` affects indirections (i.e. pointers). `Foo` doesn't 
contain any indirections, so `scope` doesn't mean anything for 
it. The compiler just ignores it. It's like you wrote `Foo x;` 
without `scope`.

`Bar` does contain an indirection, so `scope` actually matters 
and you get the error.