On Thursday, 30 December 2021 at 09:34:27 UTC, eugene wrote:
I suspect the question was asked somewhere before.
If so just give a link.
Anyway:
```d
class IoContext {
...
ubyte[] buf;
...
this(uint bufSize) {
buf = new ubyte[bufSize];
}
}
```
The buffer contains (ascii) string terminated with '\n'.
In order to print it not as an array of numbers (buf is 1024
bytes long),
but as usual string I do
```d
char[] s = cast(char[])ioCtx.buf[0 ..
strlen(cast(char*)ioCtx.buf.ptr) - 1];
// -1 is to eliminate terminating '\n'
writefln("got '%s' from '%s:%d'", s, client.addr, client.port);
```
Is there some more concise/elegant way to do that?
Of course, I could use old good printf() instead:
```d
printf(
"got '%s' from '%s:%d'\n",
ioCtx.buf.ptr, // '\n' still there
toStringz(client.addr),
client.port
);
```
but I want to use D stdlib, not libc.
Unless I'm misunderstanding:
```d
import std.algorithm : until;
writefln("got '%s' from '%s:%d'",
(cast(char[])ioCtx.buf[]).until('\n'), client.addr, client.port);
```
Note that this does not save the "sliced" version of the buffer,
so if you wanted to just search for the `\n` once, and keep using
it, then you may want to use an algorithm that slices off
everything until the character.
-Steve
