On Wednesday, 20 July 2022 at 16:15:33 UTC, Salih Dincer wrote:
On Wednesday, 20 July 2022 at 09:18:29 UTC, anonymouse wrote:
Given an array of arbitrary dimensions, I would like to
accomplish three things:
1) verify that it is rectangular (e.g. all elements
have the same length, all sub-elements have the same length,
etc.)
2) flatten and return the flattened copy
3) transpose and return the transposed copy
Yesterday, I published an example of a lesson we developed with
Ali. It's same `transpose()` when I add extra `swap()` for
you. I hope it works for you.
Hello Salih, thanks for responding. I'm not seeing the transpose
function here. What I meant by transpose is, given the following:
```d
auto array = [
[111, 112, 113, 114],
[121, 122, 123, 124],
[131, 132, 133, 134],
[141, 142, 143, 144]
]
```
after applying transpose(), you'd get back the following in
return:
[
[111, 121, 131, 141],
[112, 122, 132, 142],
[113, 123, 133, 143],
[114, 124, 134, 144]
]
This should scale to arrays of all dimensions, so the row vector
(1D array):
[100, 200, 300, 4000]
would transpose to:
[[100],
[200],
[300],
[400]]
In general, the transpose of any array yields an array with its
shape reversed. For example, the following array of shape [2, 4,
5]:
```d
auto array = [[
[111, 112, 113, 114, 115],
[121, 122, 123, 124, 125],
[131, 132, 133, 134, 135],
[141, 142, 143, 144, 145]
], [
[211, 212, 213, 214, 125],
[221, 222, 223, 224, 225],
[231, 232, 233, 234, 235],
[241, 242, 243, 244, 245]
]]
```
would become this array of shape [5, 4, 2] after transpose, with
its columns becoming its rows and its rows becoming its columns:
```d
[[[111, 211],
[121, 221],
[131, 231],
[141, 241]],
[[112, 212],
[122, 222],
[132, 232],
[142, 242]],
[[113, 213],
[123, 223],
[133, 233],
[143, 243]],
[[114, 214],
[124, 224],
[134, 234],
[144, 244]],
[[115, 215],
[125, 225],
[135, 235],
[145, 245]]]
```
Thanks,
--anonymouse
