On Sunday, 24 July 2022 at 23:48:59 UTC, Adam D Ruppe wrote:
On Sunday, 24 July 2022 at 23:12:46 UTC, pascal111 wrote:
[...]
The D things in std.stdio, writef and readf, use %s to just
mean default for the given type. Since you passed it an int,
the function knows it got an int (this is different than C,
where the function only knows the format string so it requires
you to get it right) and just automatically picks a default
representation to scan.
You can writef("%s %s", "foo", 5); and it will see "foo" is a
string and thus do it as a regular %s then see 5 is an int and
since it knows, and you asked for just the default as-string
representation, it will convert just like %d would.
It's like an automatic figuring for the data type.
