On Monday, 25 July 2022 at 11:14:56 UTC, pascal111 wrote:
On Monday, 25 July 2022 at 09:36:05 UTC, ryuukk_ wrote:
Here is the way to do it with `writefln` (i think)
```D
import std;
import core.stdc.string;
void main()
{
const(char)[] ch = "Hello World!";
const(char)[] ch2 = "abc";
const(char)* p;
p = &ch[0];
p++;
auto str = p[0 .. strlen(p)];
writefln("%s", str);
}
```
Note that i removed your `.dup` it is unecessary, string
literals needs `const(char)`
After looking at the doc, `writefln` needs a slice, so we just
do that and pass it
I tried your advice with two ways; once with a constant and
other with an array, but the result isn't the same. The array
case has more letters in the output.
module main;
import std.stdio;
import core.stdc.stdio;
import core.stdc.string;
int main(string[] args)
{
const(char)[] ch1 = "Hello World!";
char[] ch2="Hello World!".dup;
const(char) *p1;
char *p2;
p1=ch1.ptr;
p2=ch2.ptr;
writeln(p1[0..strlen(p1)]);
writeln(p2[0..strlen(p2)]);
return 0;
}
Runtime output:
https://i.postimg.cc/sfnkJ4GM/Screenshot-from-2022-07-25-13-12-03.png
`ch1`is a string literal, just like in C, it is null terminated
`ch2` is a GC allocated char array, it is NOT null terminated
`strlen` is the lib C function, it counts strings up to `\O`
for `p1` it'll print correctly, it is a pointer from the null
terminated string
for `p2` strlen doesn't make sense, since it is a pointer from a
string that is NOT null terminated
