Re: typeof(func!0) != typeof(func!0())

[Andrey Zherikov via Digitalmars-d-learn]

But the question is still opened: why is `typeof(U().func!0)` not 
the same as `typeof(U().func!0())`?

There is also inconsistency within UFCS - type depends on whether 
function is a member or standalone (even if I replace `auto ref` 
with `ref U`):
```d
struct U
{
    ref U func(int i)() { return this; }
}
ref U func2(int i)(ref U u) { return u; }
void main()
{
    U u;
    pragma(msg, typeof(u.func!0));	// pure nothrow @nogc ref 
@safe U() return
    pragma(msg, typeof(u.func2!0));     // U
}
```