On Friday, 23 September 2022 at 14:38:35 UTC, Jesse Phillips
wrote:
You should be explicit with requirements.
Sorry, generally what I speak is Turkish language. So, I speak
English as a foreign language but it's clear I wrote. What do you
think when you look at the text I've pointed to following?
On Thursday, 22 September 2022 at 10:53:32 UTC, Salih Dincer
wrote:
Is there a more accurate way to delete **the '\0' characters at
the end of the string?**
* character**S**
* at the **END**
* of the **STRING**
```d
auto splitz(string s) {
return s.splitter('\0')
.filter!(x => !x.empty);
}
```
By the way, if we're going to filter, why are we splitting?
Anyways! For this implementation, indexOf() is a powerful enough
tool. In fact, it's pretty fast, as there is a maximum of the \0
8 characters possible and when those 8 '\0' are at the end of the
string! For example:
```d
void main()
{
string[] samples = ["the one\0", "the two\0\0", "the
three\0\0\0",
"the four\0\0\0\0", "the five\0\0\0\0\0",
"the six\0\0\0\0\0\0", "the
seven\0\0\0\0\0\0\0",
"the eight\0\0\0\0\0\0\0\0"];
import std.stdio : writefln;
foreach(s; samples)
{
auto start = s.length - 8;
string res = s.splitZeros!false(start);
writefln("%(%02X%)", cast(ubyte[])res);
}
}
string splitZeros(bool keepSep)(string s, size_t start = 0)
{
auto keep = keepSep ? 0 : 1;
import std.string : indexOf;
if(auto seekPos = s.indexOf('\0', start) + 1)
{
return s[0..seekPos - keep];
}
return s;
}
```
SDB@79
