On 3/3/23 12:45, Joe wrote:
> I had tried changing B.x1() to:
>
> `ref X x1() { return &xs[0]; }`
>
> but the compiler didn't accept it.
Yeah, that wouldn't work because the return expression is an X*.
Even though 'ref' is implemented as a pointer behind the scenes, that
syntax is not legal.
> It's a bit weird that by taking the address of calling B.x1() and thus
> getting an X*
Agreed but that's how it is. Taking the address of a reference produces
an X*.
> I had to *dereference* that to pass it to the helper
> function of A.mfd() which actually takes a `ref C` argument.
Yep, all of that makes sense. :)
Ali
