Re: Why does Nullable implicitly casts when assigning a variable but not when returning from a function?

[Lettever via Digitalmars-d-learn]

On Wednesday, 10 April 2024 at 21:38:22 UTC, Andy Valencia wrote:

On Wednesday, 10 April 2024 at 20:41:56 UTC, Lettever wrote:

```
import std;

Nullable!int func() => 3;
void main() {
    Nullable!int a = 3;
    //works fine
    Nullable!int b = func();
    //does not compile
}

Why make func() Nullable? It just wants to give you an int, right? Making it a function returning an int fixes this.

Andy

Its an example