Is it possible to declare a partially initialized struct?
I would have thought that doing it like this would work:
```
struct S {
int[100] a = void;
int b = 0;
}
```
But when I declare a variable of type `S`, the array `a` is
initialized, so it seems that the `= void` is not playing any
role here.
Of course `S s = void;` works for `a`, but then `b` is not
initialized. I tried doing:
```
struct S {
@disable this ();
auto this(int b) {
this.b = b;
a = void;
}
int[100] a;
int b = 0;
}
```
But that doesn't even compile.
I'm currently settling for something like:
```
auto placeS(string name)() => iq{
S $(name) = void;
$(name).b = 0;
}.text;
```
and then declare with `mixin(placeS!"s");`.
Is there a better way?
Cheers!
Arredondo.
