On Sat, 21 May 2011 10:54:54 +0200, Matthew Ong <[email protected]> wrote:
mixin template AType(alias T, U, alias V){
class T : ClassC { // Class level Template
This gives you a class called T. You seem to want it to have the name
you pass as a string, in which case you have to use string mixins.
private:
U value;
public:
this(){}
void print(){}
mixin V;
} // End Class
}
class ClassC {}
mixin template btype() {
void someFunction() {}; // Content of a class.
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
As mentioned above, in order to use the name from the template parameter
you need to use string mixins. Here is how I would do it:
string ATypeGenerator( string name ) {
return "class " ~ name ~ " : ClassC {
private:
U value;
public:
this(){}
void print(){}
mixin V;
}";
}
mixin template AType( string name, U, alias V ) {
mixin( ATypeGenerator( name ) );
}
mixin AType!("ClassB", string, btype);
void main() {
ClassC r = new ClassB();
}
--
Simen
