On 01.07.2011 22:18, Ali Çehreli wrote:
On Fri, 01 Jul 2011 21:18:45 +0200, simendsjo wrote:
What is contained within this byte?
(T[0]).sizeof == 0, why isn't void also 0?
void* can point to any data, in which case it is considered to be
pointing at the first byte of the data. Having a size of one makes it
point to the next byte when incremented:
int i;
void * v =&i; // first byte
++v; // second byte
Similarly, an empty struct has a size of one:
import std.stdio;
struct S
{}
void main()
{
assert(S.sizeof == 1);
}
But in that case it is needed to identify S objects from one another just
by having different addresses. The following array's data will occupy 10
bytes:
S[10] objects;
assert(&(objects[0]) !=&(objects[1]));
Ali
Needed some time to digest your answer, but it makes sense now. Thanks.
