On Sun, 16 Oct 2011 18:24:26 -0400, Timon Gehr <timon.g...@gmx.ch> wrote:
On 10/13/2011 01:46 PM, Steven Schveighoffer wrote:
On Thu, 13 Oct 2011 06:57:09 -0400, Cheng Wei <riverch...@gmail.com>
wrote:
== Quote from Steven Schveighoffer (schvei...@yahoo.com)'s article
On Wed, 12 Oct 2011 09:46:57 -0400, Trass3r <u...@known.com> wrote:
>> I believe that the primary reasoning for allowing the implicit
>> conversion
>> between int and dchar is so that code like this
>>
>> dchar c = 'a' + 7;
>
> That's a '+' though, not a '~'.
Jonathan meant this better example ;)
string s = "hello";
s ~= 'a' + 7;
It's still fine if '~' does not allow implicit casting but '+' does.
'a' + 7 -> 'h' which is already a dchar. So it can be appended to s
without casting.
A + B where the types of A and B are integral goes through integer
promotion rules, inherited from C. Like them or not, they are very
unlikely to change. This means dchar + int promotes to int, not dchar.
Actually uint afaik.
Hm... int can hold all dchar values, so I'd expect it to promote to int
before uint.
testing:
void main()
{
dchar d;
auto x = d + 5;
pragma(msg, typeof(x).stringof);
}
outputs: uint
so you are right! Seems like an oversight...
-Steve
