Re: Const lazy arguments?

[Ben Davis]

If you had a "const lazy SomeClass con" and a "lazy SomeClass mut", you 
could write "mut.x=y" but not "con.x=y". I think.

On 11/01/2012 04:46, bearophile wrote:
I ask here first before submitting about this to Bugzilla.
If lazy arguments can't be lvalues:


void foo(lazy int x) {
     x = x;
}
void main() {}

==>
test.d(2): Error: lazy variables cannot be lvalues


What's the point of accepting const lazy arguments?

void foo(const lazy int x) {}
void main() {}

Bye,
bearophile