04.03.2012 3:42, Andrej Mitrovic пишет:
[...code...]
I want to avoid writing "check()" twice. I only have to statically
check a field of a member if it's of a certain type (Foo).
One solution would be to use a boolean:
void test(T)(T t)
{
bool isTrue = true;
static if (is(T == Foo))
isTrue = t.isTrue;
if (isTrue)
check();
}
But that kind of defeats the purpose of static if (avoiding runtime
overhead). Does anyone have a trick up their sleeve for these types of
situations? :)
Alias maybe?
void test(T)( T t ) {
enum TRUE = true;
static if( is(T == Foo) ) {
alias t.isTrue isTrue;
} else {
alias TRUE isTrue;
}
if( isTrue ) {
check();
}
}
This will still insert a redundant check for one of instantiations, but
compiler should be able to deal with 'if(true)' checks.
