On Mon, Mar 05, 2012 at 08:41:53PM +0000, Justin Whear wrote:
> On Mon, 05 Mar 2012 12:16:14 -0800, H. S. Teoh wrote:
>
> > I know D doesn't really have RTTI yet, but I'm experimenting with
> > "faking" it by doing something like:
> >
> > class A {
> > string prop1;
> > int prop2;
> > ...
> > void serialize() {
> > __serialize(this);
> > }
> > }
> >
> > void __serialize(T)(T obj) {
> > writeln(typeid(obj));
> > foreach (name; __traits(derivedMembers, T)) {
> > writefln("%s = %s", name,
> > __traits(getMember,obj,name));
> > }
> > }
> >
> > The only thing is, serialize() has to be declared in every derived
> > class, because T needs to be known at compile-time. Is there a way to
> > "automate" this? I.e., automatically insert the serialize() boilerplate
> > code into derived classes?
> >
> > (P.S. D just took on brand new levels of cool when I realized I could
> > do something like this. Imagine doing this with C++ templates... ugh!
> > What a painful thought!)
> >
> >
> > T
>
> The normal approach is to use a string mixin statement in each derived
> class:
>
> template Serializable()
> {
> enum Serializable = q{...your code here...};
> }
>
> class B : A
> {
> mixin(Serializable);
> }
>
> Unfortunately, I don't believe there's any mechanism to order derived
> classes to automatically perform the mixin.
OK, it's a bit ugly I supopse, but I can live with that.
Is there a way to tell whether or not a given class is a derived class
or not? I'm using the Serializable template to insert serialize() into
the class, and for derived classes I need to insert "override void
serialize() ..." but for the base class I have to omit "override". How
can I detect this in the template?
Thanks!
T
--
No! I'm not in denial!
