On Fri, 30 Mar 2012 19:52:50 +0200, simendsjo <[email protected]> wrote:
On Fri, 30 Mar 2012 17:13:25 +0200, Simen Kjærås
<[email protected]> wrote:
Indeed. The thing is - U is basically *set* by the isExpression. It says
'yes, there is such a U, so I'll add it to the local scope.'. This means
that U will be set for the entire scope within which the static if
exists.
Due to the way the criteria are phrased, U is defined when the criteria
are not met, and as such are defined in the else clause instead of the
if clause.
{ // Outer scope starts here.
static if ( !is( const(int) t == const(U), U ) ) {
// isExpression returned false, so U is undefined
} else {
// But here it is defined, because we're still in the same,
// broader scope.
}
}
// And here it's no longer defined.
Was that any better? I admit I didn't understand it at first either, but
then I remembered that static if does not introduce a new scope. That
helped.
I knew static if didn't create a new scope, but I still thought U would
not be defined if it didn't match, but it seems it is defined just by
existing in the scope.
I had a bug when I tried to reproduce the behavior: I used typeof(U),
which is, of course, not possible as U is a type :)
Thanks for the explanation. Allowed to use D at work yet btw?
Not really. I use it a lot for scripts and fast prototyping, but it's
not the most flexible of organizations. Could use it for internal tools,
likely.
