Is there a way in which to pass a function as input to another function, with
the arguments of the first function already determined?
The case I'm thinking of is one where I have a function which wants to take a
random number generation scheme, and use it on several occasions, without having
any info on that scheme or its parameters.
Here's a little test attempt I made:
////////////////////////////////////////////////////
import std.random, std.range, std.stdio;
void printRandomNumbers(RandomNumberGenerator)(RandomNumberGenerator rng,
size_t n)
{
foreach(i; 0..n)
writeln(rng);
}
void main()
{
foreach(double upper; iota(1.0, 2.0, 0.2) ) {
double delegate() rng = () {
return uniform(0.0, 1.0);
};
printRandomNumbers(rng,10);
}
}
////////////////////////////////////////////////////
... which just prints out: "double delegate()" over many lines.
What am I doing wrong here? And is there any way to avoid the messy business of
defining a delegate and just hand over uniform(0.0, 1.0) ... ?
