Re: Compute in one pass 3 tokens position

[bioinfornatics]

Le lundi 30 avril 2012 à 14:52 +0200, bioinfornatics a écrit :
> Hi,
> I would like to know how compute in on pass 3 tokens position in a
> sequence.
> curently i do:
> File f = File( "reader.d", "r" );
> scope(exit) f.close();
> char[1024] buffer;
> char[] content = f.rawRead(buffer);
> char[sizediff_t] token = ['(', '{', ';'];
> auto position = map!( a => content.countUntil( a ) )( [ ['('], ['{'],
> [';'] ] );
> 
> 
> if i use reduce instead map the build fail
> 

Anyone know how to know the position of 3 token in one sequence in one
pass?

tok1 = a
tok2 = b
tok3 = c
seq =  blah count me
b=> 0 a=>2 c=>5
iterate over sequence if token not yet seen count the number of
iteration for know in which column it is located. Example own written on
the fly)

sizediiff_t[] countUntil( in char[] seq; char[] tokens ){
  bool isSearching = true;
  size_t index = 0;
  sizediiff_t[] position = new sizediiff_t[](tokens.length);
  while (isSearching){
    if (index >⁼ seq.length)
      isSearching = false;
    else if (! find( position, -1) // al token found we can stop;
      isSearching = false;
    else{
      sizediiff_t tmp = countUntil( tokens, [seq[index]]);
      if (countUntil( tmp != -1 && position[tmp] != -1)
        position[tmp] = index;
      index++;
    }
  }
}