On Wed, 16 May 2012 15:24:33 +0100, ref2401 <refacto...@gmail.com> wrote:
i have an array of ubytes. how can i convert two adjacent ubytes from
the array to an integer?
pseudocode example:
ubyte[5] array = createArray();
int value = array[2..3];
is there any 'memcpy' method or something else to do this?
You don't need to "copy" the data, just tell the compiler to "pretend"
it's a short (in this case, for 2 bytes) then copy the value/assign to an
int. e.g.
import std.stdio;
void main()
{
ubyte[5] array = [ 0xFF, 0xFF, 0x01, 0x00, 0xFF ];
int value = *cast(short*)array[2..3].ptr;
writefln("Result = %s", value);
}
The line:
int value = *cast(short*)array[2..3].ptr;
1. slices 2 bytes from the array.
2. obtains the ptr to them
3. casts the ptr to short*
4. copies the value pointed at by the short* ptr to an int
You may need to worry about little/big endian issues, see:
http://en.wikipedia.org/wiki/Endianness
The above code outputs "Result = 1" on my little-endian x86 desktop
machine but would output "Result = 256" on a big-endian machine.
R
--
Using Opera's revolutionary email client: http://www.opera.com/mail/
