On Wednesday, 6 June 2012 at 18:12:39 UTC, Namespace wrote:
If i have this code:
class Bar {
public:
Foo GetFoo() {
return this._foo;
}
alias GetFoo this;
}
to allow access to Foo methods from Bar i get the error, that
"GetFoo" isn't a property if i use -property.
Why?
The solution is to set @property before "Foo GetFoo()" but why
must GetFoo a property? What if i don't want to declare GetFoo
as a property? I cannot use it with alias this?
Because name lookup with alias this is implemented as simple
rewriting of expressions.
auto bar = new Bar();
bar.hoge;
If class Bar doesn't have member hoge, it is rewritten as:
bar.GetFoo.hoge;
After that, if Bar.GetFoo.hoge is a property, bar.GetFoo is
converted to bar.GetFoo().hoge as like other property functions.
If Bar.GetFoo is not a property and you use -property switch,
compiler shows "not a property" error because GetFoo is not a
property.
There is no magic.
