On 08/24/2012 12:14 AM, Piotr Szturmaj wrote:
Hi,I found this code of std.range.iota's Result struct: @property inout(Value) front() inout { assert(!empty); return current; } What's the purpose of inout on parameterless functions?
It is a method of a struct, therefore it is not parameterless, but has a hidden parameter. 'inout' qualifies the implicit 'this' reference. Inside the method body, typeof(this) is inout(Result).
