timotheecour:
//attempt#2
//also tried to just pass x=>a.fun2(x), but then
ParameterTypeTuple doesn't work with lambdas.
I think "x => a.fun2(x)" isn't an anonymous function, it's templated.
Bye, bearophile
timotheecour:
//attempt#2
//also tried to just pass x=>a.fun2(x), but then
ParameterTypeTuple doesn't work with lambdas.
I think "x => a.fun2(x)" isn't an anonymous function, it's templated.
Bye, bearophile