On Thursday, 11 October 2012 at 15:21:01 UTC, bearophile wrote:
Damian:
I come from a pascal background and we could use:
div integral division operator
/ floating point division operator
Two operators for the two different operations is a design
better
than C, that is bug-prone.
So my question is, how does D force floating point division on
integrals?
At the moment i do this, but i was hoping for an easier way:
int n1 = 10, n2 = 2;
float f = cast(float)(cast(float)(n1 / n2));
That's not good, it performs an integer division, followed by
two
float casts.
Note: float is useful only if you have many of them, or if you
pass/return pairs of them. A single float is not so useful.
A solution:
int n1 = 10, n2 = 2;
const f = n1 / cast(double)n2;
Using type inference is useful, as it doesn't hide an integer
result if your code is wrong.
Bye,
bearophile
Ah i see, thankyou for the explanation.
