Rob, your original code:
// d-linked list with templated payload
struct d_list( T )
{
struct node
{
T payload;
node* pred;
node* succ;
}
node* head;
node* tail;
}
compiles just fine for me (Linux 32bits, DMD 2.060).
Even with some exercising, the template doesn't fail:
void main()
{
auto list = d_list!(int)();
}
On Thu, Nov 8, 2012 at 6:49 PM, Rob T <r...@ucora.com> wrote:
> On Thursday, 8 November 2012 at 15:19:56 UTC, Dmitry Olshansky wrote:
>
>>
>> Naturally C++ doesn't have nested struct definitions.
>>
>>
> I don't have a nested struct, the struct definition defines the type only,
> and the nodes are allocated as pointers from a new operation when the list
> is composed. The node struct has a member var that may or may not be a
> struct type, it does not matter, and C++ will allow a member data type to
> be a struct just fine.
>
>
> I also want to template the recursive structure itself to specify the
>>> value type, ie struct R(T){ T value; d_list!R Rlist; }, but I left that
>>> out to keep the example more simple.
>>>
>>>
>> I've been stuck on this problem all day, so any help is appreciated!
>>>
>>
>> See if it helps.
>>
>
> I tried moving the node struct outside the d_list struct, but no luck, and
> I think it should not matter anyway since I can get it to work in that way
> without a template.
>
> The solution so far is to do it the C++ way, using pointers, which sucks.
>
> I think in this case the D template should work just fine, and the problem
> is either a bug or a design flaw with how templates are evaluated.
>
> I'll wait a bit longer for more comments before filing a bug report.
>
> --rt
>
>
>
