Re: is(...) with alias this

[monarch_dodra]

On Saturday, 5 January 2013 at 22:09:45 UTC, Philippe Sigaud 
wrote:
I think the alias this transformation is done 'before' any usual
conversion. I guess it's a real replacement inside the code 
(I'm not sure
how to explain my feeling).
But in any case, since OhWhy!(float) type is ... OhWhy!(float), 
I agree
this should fail.

Agreed. This warrants a ticket in bugzilla.