On 03/21/2013 01:02 PM, Stefan wrote:
> On Wednesday, 2 May 2012 at 15:27:58 UTC, Jabb wrote:
>
>> import std.algorithm;
>> void main() {
>> uint[string] counts = [ "a":4, "b":5, "c":3, "d":1 ];
>> string[] keys = counts.keys;
>>
>> sort!((a, b) { return counts[a] > counts[b]; })(keys);
>> }
>
> Did you try
> string[] keys = counts.keys.dup;
> ?That should be ok. Unlike .byKey, .keys is eager; all of the keys are in the returned slice by the time it returns.
Ali
