Re: How to expand an expression along with a parameter tuple?

[TommiT]

On Monday, 17 June 2013 at 11:15:24 UTC, Artur Skawina wrote:
On 06/17/13 11:32, TommiT wrote:
On Monday, 17 June 2013 at 07:20:23 UTC, Ali Çehreli wrote:

The following does not answer the question of expanding but 
at least foo() receives [30, 70, 110] :)

import std.stdio;
import std.algorithm;
import std.array;
import std.range;

int[] arr = [ 1, 3, 5, 7, 11 ];

void foo(T)(T[] values...)
{
    writeln(values);
}

void bar(T)(T[] values...)
{
    foo(arr
        .indexed(values)
        .map!(a => a * 10)
        .array);
}

void main()
{
    bar(1, 3, 4);
}

Ali

Yeah, that would work. I'd hate the overhead though.

   void bar(T...)(T values) {
      T tmp;
      foreach (i, ref v; values)
         tmp[i] = arr[v]*10;
      foo(tmp);
   }

artur

Cool, I didn't know that you could create multiple variables like 
that (T tmp).