On Wednesday, June 19, 2013 16:35:16 Ali Çehreli wrote:
> On 06/19/2013 04:29 PM, Agustin wrote:
> > Hello guys, my question is, its possible to write a mixin in a class,
> > then if that class is inherited, the mixin will be written again instead
> > of written the mixin again in the class child, for example:
> >
> > Class A(T)
> > {
> >
> > mixin(WriteFunctionFor!(A));
> >
> > }
> >
> > Class B : A(B)
> > {
> >
> > ... -> mixin is written for B without need to write
> > ("mixin(Write...))")
> >
> > }
> >
> > Class C : A(C)
> > {
> >
> > ... -> mixin is written for C without need to write
> > ("mixin(Write...))")
> >
> > }
>
> Yes:
>
> import std.stdio;
>
> template WriteFunctionFor(T)
> {
> T data;
>
> void foo()
> {
> writefln("I am working with a %s.", T.stringof);
> }
> }
>
> class A(T)
> {
> mixin WriteFunctionFor!T;
> }
>
> class B : A!B
> {}
>
> class C : A!C
> {}
>
> void main()
> {
> auto b = new B();
> b.foo();
>
> auto c = new C();
> c.foo();
> }
>
> The output:
>
> I am working with a B.
> I am working with a C.
Ah, you're right. That will work. I misread the question. I thought that he
was asking whether mixins in the base class magically got mixed in again into
the derived class, which they don't.
- Jonathan M Davis
