On Monday, 21 October 2013 at 16:22:29 UTC, Krzysztof Ciebiera wrote:
What I want to do is: I want to take a look at every single solution and extend it if it is possible (eg. if solution contains obbects a,b,c it can also contain d).

void main()
{
        import std.stdio;
        int[][] data = [ [ 0, 1, 2], [2, 3, 4] ];
        foreach(ref arr; data)
        {
                if (arr[0] == 2)
                        arr ~= 5;
        }
        writeln(data);
}

?

(original arrays can be also allocated with extra capacity to avoid copy-allocation upon extending)

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