Re: Task to throw away string parts, use joiner and splitter not very successful

[Rémy Mouëza]

You can use `std.conv.to` to convert the dchar[] back to a string, 
adding `.to!string` at the end of the dchar[] array you want to convert.

Also not that there exists two similar functions to the lazy evaluated 
splitter() and joiner() in std.array: the eagerly evaluated split() and 
join(); being eager make the code looks more straightforward (no 
`.array` or `.to!string`).

    import std.stdio;
    import std.array;
    import std.algorithm;

    void eager () {
        string name = "thiš.ìs.à.çtriñg";
        auto parts  = name.split (".");
        parts.popBack;
        auto cut    = parts.join (".");
        cut.writeln;
    }

    void lazy_ () {
        string name = "thiš.ìs.à.çtriñg";
        auto parts  = name.splitter (".");
        parts.popBack;
        auto cut    = parts.joiner (".").array.to!string;
        cut.writeln;
    }

    void main () {
        eager ();
        lazy_ ();
    }

The program prints:
thiš.ìs.à
thiš.ìs.à

On 01/01/2014 08:40 AM, Dfr wrote:
And one more problem here:

     string name = "test";
     auto nameparts = splitter(name, '.');
     writeln(typeof(joiner(nameparts, ".").array).stringof);

This prints "dchar[]", but i need char[] or string, how to get my
'string' back ?


On Tuesday, 31 December 2013 at 20:49:55 UTC, Dfr wrote:
Hello, i have string like "this.is.a.string" and want to throw away
some parts separated by dots, here is first attempt:

name = "this.is.a.string"; // <-- want to make "this.is.a" from this
auto nameparts = splitter(name, '.');
auto name1 = joiner(nameparts[0 .. $-1], '.');

And got this error: "Error: Result cannot be sliced with []"

So, kinda fixed it (correct way?):

name = "this.is.a.string";
auto nameparts = splitter(name, '.').array;
auto name1 = joiner(nameparts[0 .. $-1], '.');

got this:

Error: template std.algorithm.joiner does not match any function
template declaration. Candidates are:
/usr/include/dmd/phobos/std/algorithm.d(2846):
std.algorithm.joiner(RoR, Separator)(RoR r, Separator sep) if
(isInputRange!RoR && isInputRange!(ElementType!RoR) &&
isForwardRange!Separator && is(ElementType!Separator :
ElementType!(ElementType!RoR)))

Stuck here, thank you for any help.